By using this following model calculation anyone can able to find the tile requirement and the cost required easily. For this calculation we used 12’ x 10’ (inner) room.
Room size = 12’ x 10’
Area of the room = 12 x 10 = 120 square feet.
We also provide tiles at the junction of floor and
wall (Skirting). So we need to calculate that area also. Assume the height of
the skirting will be 4”
Length of the skirting = (2 x 12’) + (2 x 10’) =
44’ [ Inner Perimeter of the Room]
Now Area of skirting = 44’ x (4”/12) = 14.52 square
feet
Total Tile laying square feet = 120 + 14.52 = 134.52
square feet
Let us take 150 square feet including wastage
Second, we have to find the cement mortar for laying
the tile. For this we can assume 1:6 ratio mortar. It means 1-part cement and
6-part sand. mortar thickness will be 2”
Total mortar volume
required = 150 x (2”/12) = 25 cubic feet.
Quantity of sand = (6/7) x 25 x 1.33 = 28.5 cubic feet
= take 29 cubic feet of sand.
Quantity of cement = (1/7) x (25/35.29) x 1.33 x
(1440/50) = 3.87 bags = 4 bags of cement.
Here 35.29 conversion factor, 1.33 = dry factor, 1440
= density of cement, 50= Kg per bag.
You can fill the rate
details in your area and you will easily get the details
|
Materials |
Quantity |
Unit rate |
Cost |
|
TIles |
150 square feet |
|
|
|
Sand |
29 cubic feet |
|
|
|
Cement |
4 bags |
|
|
|
Joint Filler |
1 |
|
|
|
Labour charge |
150 square feet |
|
|
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